Derivation

Whatever generates a linearly converging iteration sequence, can we deduce information about the limit of the sequence from already calculated values?

For a linear method, [Maple Math] , or, for sufficiently large [Maple Math] ,

> lambda=(p[n+1]-pe)/(p[n]-pe);

[Maple Math]

> lambda=(p[n+2]-pe)/(p[n+1]-pe);

[Maple Math]

with [Maple Math] the exact solution, or

> eq:=(p[n+1]-pe)/(p[n]-pe)-(p[n+2]-pe)/(p[n+1]-pe)=0;

[Maple Math]

which can be solved for the true solution, [Maple Math] :

> pexact:=solve(eq,pe);

[Maple Math]

which is more commonly written as [Maple Math] .

This formula allows us to calculate a more accurate approximation to the real solution using only already calculated values in the series. This can be very useful when each iteration is costly in terms of computer resources.