Example

Consider now the case where a single precision number is represented by 32 bits, one for the sign, 7 for the exponent and 24 for the mantissa. Then the 32 bit combination, 0 0111010 101100110000010000000000, represents the positive number with and in binary notation. (We assume and ). In other words,

> e1:=convert(0111010,decimal,binary);

> Mantissa:=convert(101100110000010000000000,decimal,binary);

> number:=evalf(Mantissa*16^(e1-64));